((x-2)^3+8)/x=x^2-6x+12

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Solution for ((x-2)^3+8)/x=x^2-6x+12 equation: 



((x-2)^3+8)/x=x^2-6x+12

We move all terms to the left:

((x-2)^3+8)/x-(x^2-6x+12)=0



Domain of the equation: x!=0

x∈R



We get rid of parentheses

-x^2+((x-2)^3+8)/x+6x-12=0

We multiply all the terms by the denominator


-x^2*x+((x-2)^3+8)+6x*x-12*x=0



We calculate terms in parentheses: +((x-2)^3+8), so:

(x-2)^3+8



We add all the numbers together, and all the variables

-x^2*x-12x+((x-2)^3+8)+6x*x=0

Wy multiply elements

-1x^3+6x^2-12x+((x-2)^3+8)=0



We calculate terms in parentheses: +((x-2)^3+8), so:

(x-2)^3+8



We do not support expression: x^3

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